The degree of hydrolysis of 0.1 M `NH​_4​Cl` solution is 1%. If the concentration of `NH_4​Cl` is made 0.4 M, what is the new degree of hydrolysis :-

The degree of hydrolysis of 0.1 M RNH_(3)Cl solution is 1.0%. If the concentration of RNH_(3)Cl is made 0.4 M, what is the new degree of hydrolysis (in percentage)?

The degree of hydrolysis of 0.1 M RNH_(3)Cl solution is 1.0%. If the concentration of RNH_(3)Cl is made 0.4 M, what is the new degree of hydrolysis (in percentage)?

The degree of hydrolysis of 0.1 M RNH_(3)Cl solution is 1.0%. If the concentration of RNH_(3)Cl is made 0.4 M, what is the new degree of hydrolysis (in percentage)?

P^(H) of 0.02 M NH_(4)Cl solution is

The degree of hydrolysis of 0.01 M NH_(4)CI is (K_(h) = 2.5 xx 10^(-9))

The degree of hydrolysis of 0.01 M NH_(4)CI is (K_(h) = 2.5 xx 10^(-9))

The degree of hydrolysis of 0.1 M solution of conjugate base of HA is 0.01. Find the H^+ concentation in 0.4 M solution of A^- :

Calculate the Van't Hoff factor when 0.1 mol NH_(4)Cl is dissolved in 1 L of water. The degree of dissociation of NH_(4)Cl is 0.8 and its degree of hydrolysis is 0.1 .

Calculate the Van't Hoff factor when 0.1 mol NH_(4)Cl is dissolved in 1 L of water. The degree of dissociation of NH_(4)Cl is 0.8 and its degree of hydrolysis is 0.1 .

Calculate the Van't Hoff factor when 0.1 mol NH_(4)Cl is dissolved in 1 L of water. The degree of dissociation of NH_(4)Cl is 0.8 and its degree of hydrolysis is 0.1 .