An electron travels in a circular path of radius 20 cm in a magnetic field of `2xx10^(-3)T`. Calculate the speed of the electron. What is the potential difference through which the electron must be accelerated to acquire this speed?

An electron travels in a circular path of radius 20cm in a magnetic field 2xx10^-3T (i) Calculate the speed of the electron (ii) What is the potential difference through which the electron must be accelerated to acquire this speed? Charge of electron =1*6xx10^(-19)C . Mass of electron =9xx10^(-31)kg .

An electron travels on a circular path of radius 10 m in a magnetic field of 2 xx 10^(–3) T. Calculate the speed of electron. What is the potential difference through which it must be accelerated to acquire this speed?

An electron having 182 eV kinetic energy is moving on a circular path in a magnetic field of 10^(-4)T . The speed of the electron is ......

An electron of energy 150ev describe a circular path in a magnetic field of 1 T. Calculate the radius of circle.

An electron is revolving in a circular path of radius 2xx10^(-10) m with a speed of 3xx10^(6) m/s. The magnetic field at the centre of circular path will be-

The potential difference through which an electron should be accelerated from rest so that it acquires a speed of 2 xx 10^(7) m/s is

An electron is moving on a circular path of radius r with speed v in a transverse magnetic field B. e/m for it will be

An electron is moving on a circular path of radius r with speed v in a transverse magnetic field B. e/m for it will be

An electron moves along a circular path of radius 10 cm. If the centripetal acceleration is 4xx10^(11) m//s^(2) , then its linear speed is