In triangle ABC, `angleA=30^(@)`, H is the orthocentre and D is the midpoint of BC. Segment HD is produced to T such that HD=DT. The length AT is equal to `lambda`BC units, then `lambda` is equal to -

In a triangle ABC, angleA=30^@ H is the orthocentre and D is the midpoint of BbarC . Segment HD is produced to T such that HD=DT. The ratio (AT)/(DC) equals to

In triangle ABC,/_A=30^(@),H is the orthocenter and D is the midpoint of BC . Segment HD is produced to T such that HD=DT. The length AT is equal to a.2BC b.3BC c.(4)/(2)BC d.none of these

In triangle A B C ,/_A=30^0,H is the orthocenter and D is the midpoint of B C . Segment H D is produced to T such that H D=D T The length A T is equal to (a). 2B C (b). 3B C (c). 4/2B C (d). none of these

In triangle A B C ,/_A=30^0,H is the orthocenter and D is the midpoint of B C . Segment H D is produced to T such that H D=D T The length A T is equal to (a). 2B C (b). 3B C (c). 4/2B C (d). none of these

In triangle A B C ,/_A=30^0,H is the orthocenter and D is the midpoint of B Cdot Segment H D is produced to T such that H D=D Tdot The length A T is equal to a. 2B C b. 3B C c. 4/2B C d. none of these

In triangle A B C ,/_A=30^0,H is the orthocenter and D is the midpoint of B Cdot Segment H D is produced to T such that H D=D Tdot The length A T is equal to a. 2B C b. 3B C c. 4/2B C d. none of these

In Delta ABC,|_(BAC)=30^(@) and H is the orthocentre,M is the mid point of BC.HM is produced to thepoint T such that HM=MT Then |AT|=lambda|BC| where lambda is

In DeltaABC , 'O' is the orthocentre, M is midpoint of BC and angleBAC = 30^(@) . The segment OM is produced to the point T such that OM = MT. Prove that AT=2BC.

In triangle ABC , AB = BC , angle B = 40 ^(@) Then angleA is equal to