The point of intersection of the plane `3x-5y+2z=6` with the straight line passing through the origin and perpendicular to the plane `2x-y-z=4` is

If the point of intersection of the plane 4x - 5y + 2z - 6 = 0 with the line through the origin and perpendicular to the plane x- 2y - 4z = 4 is P, then the distance of the point P from (1, 2,3) is

If the point of intersection of the plane 4x - 5y + 2z - 6 = 0 with the line through the origin and perpendicular to the plane x- 2y - 4z = 4 is P, then the distance of the point P from (1, 2,3) is

Equation of the passing through the origin and perpendicular to the planes x+2y+z=1 , 3x-4y+z=5 is

Equation of the passing through the origin and perpendicular to the planes x+2y+z=1 , 3x-4y+z=5 is

Equation of the passing through the origin and perpendicular to the planes x+2y+z=1 , 3x-4y+z=5 is

The line passing through the point -1, 2, 3 and perpendicular to the plane x - 2y + 3z + 5 = 0 will be

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 =0 . If the plane is perpendicular to the plane 3x - y - 2z - 4 = 0 , then the value of p is equal to

The plane x + 3y + 13 = 0 passes through the line of intersection of the planes 2x - 8y + 4z = p and 3x - 5y + 4z + 10 = 0 If the plane is perpendicular to the plane , 3x - y - 2z - 4 = 0 then the value of p is equal to

The plane x+3y+13=0 passes through the line of intersection of the planes 2x-8y+4z=pand3x-5y+4z+10=0 . If the plane is perpendicular to the plane 3x-y-2z-4=0 , then find p