The time period of an oscillating body executing SHM is 0.05 sec and its amplitude is 40 cm. The maximum velocity of particle is :

The time period of a body executing S.H.M. is 0.05 s and the amplitude of vibration is 4 cm. What is the maximum velocity of the body ?

The time period of a body executing SHM is 0.05 s. if the amplitude is 4 cm, then what will be the maximum velocity and maximum acceleration of the body?

The period of oscillation of a particle in SHM is 4sec and its amplitude of vibration is 4cm . The distance of the particle 0.5s after passsing the mean position is

Time period of a particle executing SHM is T = 1 second and its amplitude of vibration is A = 0.04 m. Determine the maximum velocity and maximum acceleration of the particle.

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

Amplitude of a particle executing SHM is a and its time period is T. Its maximum speed is

particle is executing S.H.M. If its amplitude is 2 m and periodic time 2 seconds , then the maximum velocity of the particle will be

A particle executes SHM with time period T and amplitude A . The maximum possible average velocity in time T//4 is-

A particle executes SHM with time period T and amplitude A . The maximum possible average velocity in time T//4 is-

A particle executes SHM with time period T and amplitude A . The maximum possible average velocity in time T//4 is-