A series combination of two resistors `1 Omega` each is connected to a 12 V battery of internal resistance `0.4 Omega`. The current flowing through it will be

A series combination of two resistors 1 Omega each is connected to a 12 V battery of internal resistance 0.4Omega The current flowing through it is

A resistance of 1 Omega is connected to a battery of emf 2 V and internal resistance 0.4 Omega what current is flowing through the circuit ? If another battery of double the emf is connected in series with the earlier one then current flowing in the circuit becomes double . what should be the internal resistance of battery ?

Two resistors of resistances 2 Omega and 6 Omega are connected in parallel. This combination is then connected to a battery of emf 2 V and internal resistance 0.5 Omega . What is the current flowing through the battery ?

Two resistors of resistances 2Omega and 6Omega are connected in parallel. This combination is then connected to a battery of emf 2 V and internal resistance 0.5 Omega . What is the current flowing through the battery ?

Two resistors of resistances 2Omega and 6Omega are connected in parallel. This combination is then connected to a battery of emf 2 V and internal resistance 0.5 Omega . What is the current flowing thrpough the battery ?

A network of resistor is connected to a 16 V battery with internal resistance of 1 Omega , a shown in fig. Obtain the current in each resistor.

(a) Three resistors 3Omega, 4Omega, and 12Omega are connected in parallel. What is the effective resistance of the combination? (b) If the combination is connected to a battery of emf 6V and internal resistance 0.5Omega , find the current drawn from the battery and terminal potential difference across the battery.