How large must F be in the figure shown to give the 700 g block an acceleration of `30 cm s^(-2)` ? The coefficient of friction between all surfaces is 0. 15.

The minimum acceleration that must be impprted to the cart in the figure so that the block A will not fall (given mu is the coefficient if friction between the surface of block and cart) is given by:

The minimum acceleration that must be impprted to the cart in the figure so that the block A will not fall (given mu is the coefficient if friction between the surface of block and cart) is given by:

A block of mass 8 kg is sliding on a surface inclined at an angle of 45^(@) with the horizontal. Calculate the acceleration of the block. The coefficient of friction between the block and surface is 0.6. (Take g=10m//s^(2) )

A block of mass 8 kg is sliding on a surface inclined at an angle of 45^(@) with the horizontal. Calculate the acceleration of the block. The coefficient of friction between the block and surface is 0.6. (Take g=10m//s^(2) )

A block of mass 8 kg is sliding on a surface inclined at an angle of 45^(@) with the horizontal . Calculate the acceleration of the block . The coefficient of friction between the block and surface is 0*6 ( Take g = 10 m//s^(2) )

A block of mass 8 kg is sliding on a surface inclined at an angle of 45^(@) with the horizontal . Calculate the acceleration of the block . The coefficient of friction between the block and surface is 0*6 ( Take g = 10 m//s^(2) )

A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8. The lorry is moving with an acceleration of 15 m//s^2 (g = 10ms^(-2)) . The force of friction between lorry and block is