Show that `((cos theta - cos 3theta)(sin 8theta + sin 2 theta))/((sin 5 theta - sin theta)(cos 4 theta - cos 6 theta))` = 1

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Show that ((cos theta - cos 3 theta) (sin 8 theta + sin 2 theta))/((sin 5 theta - sin theta) (cos 4 theta- cos 6 theta))=1

((cos theta - cos 3 theta ) ( sin 8 theta + sin 2 theta ))/(( sin 5 theta - sin theta )( cos 4 theta - cos 6 theta ))=

Prove that ((cos theta-cos 3 theta)(sin 8 theta +sin 2 theta))/((sin 5 theta-sin theta)(cos 4 theta-cos 6 theta))=1

Show that :((cos theta-cos3 theta)(sin8 theta+sin2 theta))/((sin5 theta-sin theta)(cos4 theta-cos6 theta))=1

Show that [(costheta -cos3theta)(sin8theta+sin2theta)]/[(sin5theta -sintheta)(cos4theta-cos6theta)]=1 .

(sin theta + cos theta)/(sin theta - cos theta) + (sin theta - cos theta)/(sin theta + cos theta)= ________

(cos theta + sin theta )/( cos theta - sin theta )-(cos theta - sin theta )/( cos theta + sin theta ) =

1 + (cos 2 theta + cos 6 theta)/(cos 4 theta) = (sin 3 theta)/(sin theta).

(sin5 theta-2sin3 theta + sin theta) / (cos5 theta-cos theta) = tan theta

(1+ sin theta - cos theta )/( 1+ sin theta + cos theta ) + (1+ sin theta + cos theta )/( 1+ sin theta - cos theta ) =