A projectile is thrown with velocity `v` at an angle `theta` with the horizontal. When the projectile is at a height equal to half of the maximum height,.
The vertical component of the velocity of projectile is.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The velocity of the projectile when it is at a height equal to half of the maximum height is.

A projectile is thrown with velocity v at an angle theta with the horizontal. When the projectile is at a height equal to half of the maximum height,. The velocity of the projectile when it is at a height equal to half of the maximum height is.

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

What is the vertical component of velocity of a projectile at its maximum height?

A projectile is thorwn with a velocity of 50ms^(-1) at an angle of 53^(@) with the horizontal Detemrine the instants at which the projectile is at the same height

A projectile is thorwn with a velocity of 50ms^(-1) at an angle of 53^(@) with the horizontal Detemrine the instants at which the projectile is at the same height

A projectile is fired with velocity making an angle theta with the horizontal. Show that it follows a parabolic trajectory. Obtain an expression for the maximum height attained by it.

A projectile is thrown with velocity v making an angle theta with the horizontal. It just crosses the top of two poles,each of height h, after 1 seconds 3 second respectively. The time of flight of the projectile is