If a projectile is fired at an angle `theta` with the vertical with velocity u, then maximum height attained is given by:-

When a projectile is fired at an angle theta w.r.t horizontal with velocity u, then its vertical component:

A projectile is fired at an angle theta with the horizontal with velocity u. Deduce the expression for the maximum height reached by it.

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

A projectile is thrown with a speed v at an angle theta with the vertical. Its average velocity between the instants it crosses half the maximum height is

For a projectile first with velocity u at an angle theta with the horizontal.

In case of a projectile fired at an angle equally inclined to the horizontal and vertical with velocity (u). The horizontal range is:-

In case of a projectile fired at an angle equally inclined to the horizontal and vertical with velocity (u). The horizontal range is:-

In case of a projectile fired at an angle equally inclined to the horizontal and vertical with velocity (u). The horizontal range is:-