[" 1वली "3.6" ए "],[" समीकरणों के युग्म ...

[" 1वली "3.6" ए "],[" समीकरणों के युग्म में बदल करके हल कीजिए: "],[qquad [" (ii) "(2)/(sqrt(x))+(3)/(sqrt(y))=2],[(4)/(sqrt(x))-(9)/(sqrt(y))=-1]]

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(2)/(sqrt(x))+(3)/(sqrt(y))=2 and (4)/(sqrt(x))-(9)/(sqrt(y))=-1

Solve: (2)/(sqrt(x))-(3)/(sqrt(y))=2 and (4)/(sqrt(x))-(9)/(sqrt(y))=-1

Solve (2)/(sqrt(x))+(3)/(sqrt(y))=2 ;(4)/(sqrt(x))+(3)/(sqrt(y))=2

Solve the following of equations : (2)/(sqrt(x))+(3)/(sqrt(y))=2 and (4)/(sqrt(x))-(9)/(sqrt(y))=-1

Solve the following system of equations: (2)/(sqrt(x))+(3)/(sqrt(y))=2,quad (4)/(sqrt(x))-(9)/(sqrt(y))=-1

Solve for x and y : 2/sqrt(x) + 3/sqrt(y) = 2 4/sqrt(x) + 9/sqrt(y) = -1

Solve the following system of equations: 2/(sqrt(x))+3/(sqrt(y))=2,\ \ \ \ 4/(sqrt(x))-9/(sqrt(y))=-1

find x and y 3/sqrt(x)+1/sqrt(x)=sqrt(x) y^2-(7)^(5/2)/sqrt(y)=0

if x=sqrt(3)+(1)/(sqrt(3)) and y=sqrt(3)-(1)/(sqrt(3)) then x^(2)-y^(2) is

Factorize : 2sqrt(2)x^3+3sqrt(3)y^3+sqrt(5)(5-3sqrt(6)x y)