The plane passing through the point `(5,1,2)` perpendicular to the line `2 (x-2) =y-4 =z-5` will meet the line in the point :

The plane passing through (5,1,2) and perpendicular to the line 2(x-2) y - 4 = z-5 meets the line in the ............. Point.

The line passing through the point -1, 2, 3 and perpendicular to the plane x - 2y + 3z + 5 = 0 will be

The staight line passing through the point (1,0,-2) and perpendicular to the plane x-2y+5z-7=0 is

The straight line passing through the point (1, 0, -2) and perpendicular to the plane x - 2y + 5z - 7 = 0 is

The equation of a line passing through point (1,2,3) and perpendicular to the plane x+2y-5z+9=0 are

Find the equation of the plane passing through the point(1,2,1) and perpendicular to the line joining the points (2,3,5) and (1,4,2).

The equation of line passing through the point (2, 3, 4) and perpendicular to plane 2x+3y+z+5=0 is