The two curves `x^2+y^2=25,2x^2-9y+18=0`

The two curves 2x^2+y^2=20,x^2-4y^2+8=0

If m is slope of common tangent of two curves 4x^2+9y^2=25 and 4x^2+16y^2=31 then find the value of the m^2 equal to

The two curves x^3 - 3x y^2 + 2 = 0 and 3x^2y - y^3 - 2 = 0 intersect at an angle of

Show that the following curves cut orthogonally x^(2)+y^(2)=25,2x^(2)-9y+18=0

The curves 4x^(2) + 9y^(2) = 72 and x^(2) - y^(2) = 5 at (3,2)

Find the intercept made on the curve x^(2)-y^(2)-xy+3x-6y+18=0 by the line 2x-y=3

The circles x^(2)+ y^(2) -6x-2y +9 = 0 and x^(2) + y^(2) =18 are such that they :

The circles x^(2)+ y^(2) -6x-2y +9 = 0 and x^(2) + y^(2) =18 are such that they :

Find the angle of intersection of the curves: x^2+y^2-4x-1=0 and x^2+y^2 - 2y - 9 =0