A vehicle is moving on a road with an acceleration `a=20 m//s^(2)` as shown in figure. The frictional coefficient between the block of mass (m) and the vehicle so that block is does not fall downward is `(g=10m//s^(2))`

Figure shown two blocks in contact sliding down an inclined surfase of inclination 30^(@) . The friction coefficient between the block of mass 4.0kg and the incline is mu _(2) =0.30 . Find the acceleration of 2.0kg block. (g = 10m//s^(2))

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

If coeffiecient of friction between the block of mass 2kg and table is 0.4 then out acceleration of the system and tension in the string. (g=10m//s^(2))

A block of mass 10 kg, moving with acceleration 2m//s^(2) on horizontal rough surface is shown in figure

A block of mass 10 kg, moving with acceleration 2m//s^(2) on horizontal rough surface is shown in figure

A box is accelerating with acceleration =20m//s^(2) . A block of mas 10 kg placed inside the box and is in contact with the verticle wall as shown. The friction coefficient between the block and the wall is mu=0.6 and take g=10 m//s^(2)

Find the acceleration of the block of mass M in the situation of figure. The coefficient of friction between the two blocks is mu_1 and that between the bigger block and the ground is mu_2 .

A cart of mass M has a block of mass m in contact with it as shown in the figure-2.133. The coefficient of friction between the block and the cart is mu . What is the minimum acceleration of the cart so that the block m does not fall ?