int(sqrt(cos theta))/(sin theta)d theta

int(sqrt(cos2 theta))/(sin theta)d theta=

Solve int(cos^(3)theta)/(1-sin theta)d theta

int cos 2theta log ((cos theta+sin theta)/(cos theta-sin theta))d theta

Evaluate: int cos2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

int (cos^(4)theta )/("sin" theta)d theta

Evaluate: int_(0)^( pi/2)sqrt(cos theta)sin^(3)theta d theta

int_(0)^((pi)/(2))(cos theta-sin theta)/((1+cos theta)(1+sin theta))d theta equals -

Integration using rigonometric identities : int ((sin theta+cos theta))/(sqrt(sin2 theta))d theta=.....

int((sin theta+cos theta))/(sqrt(sin 2theta))d theta is equal to

If sin theta+cos theta=sqrt(2) and b=(sqrt(2)(sin theta+cos theta))/(sin theta cos theta), then 'b'is equal to