The speed `v` of a car moving on a straight road changes according to equation, `v^2 = 1 + bx`, where `a and b` are positive constants. Then the magnitude of acceleration in the course of such motion : (x is the distance travelled).

The velocity of a car moving on a straight road increases linearly accroding to equation, v=1+bx , where a &b are positive constants. The acceleration in the course of such motion :(x is the displacement )

The velocity of a car moving on a straight road increases linearly accroding to equation, v=1+bx , where a &b are positive constants. The acceleration in the course of such motion :(x is the displacement )

The speed (v) of a particle moving in a circle of radius R varies with distance s as v=ks where k is a positive constant.Calculate the total acceleration of the particle

A street car moves rectilinearly from station A (here car stops) to the next station B (here also car stops) with an acceleration varying according to the law f = a - bx , where a and b are positive constants and x is the distance from station A . If the maximum distance between the two stations is x = (Na)/(b) then find N .

A particle moves in a straight line so that its velocity at any point is given by v^(2)=a+bx , where a,b ne 0 are constants. The acceleration is

The linear speed of a particle moving in a circle of radius R varies with time as v = v_0 - kt , where k is a positive constant. At what time the magnitudes of angular velocity and angular acceleration will be equal ?

The speed v of a particle moving along a straight line is given by a+bv^(2)=x^(2) where x is its distance from the origin. The acceleration of the particle is