`10^3-9^3`

For the equilibrium : HCO_(3)^(-)hArr H^(+)+CO_(3)^(2-) K=4.8xx10^(-11), [CO_(3)^(2-) ]=1.1xx10^(-3)M, [HCO_(3)^(-)]=9.8xx10^(-3)M The pH of the solution is :

Find the product: 3/10xx(-9)

Write True or False Mode of the data 2,3,9,10,3,3,9 is 10.

The mode of the distributions 2, 3, 9, 10, 9, 3, 9 is 9.

The mode of the frequency distributions 2, 3, 9, 10, 9, 3, 9, is 10.

True or false: Value of median of data 2, 3, 9, 10, 9, 3, 9 is 10.

Write True or False Mode of the data 2,3,9,10,9,3,9 is 10.

2^(10)+2^(9) .3^1+.....2.3^9+3^(10)=A-2^(11) . Find A=

Prove that : ^10P_3= "^9P_3+3^9P_2 .