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The equilibrium constant of the reaction...

The equilibrium constant of the reaction `A_(2)(g)+B_(2)(g)hArr2AB(g)` at `100^(@)C` is 50. If a one litre flask containing one mole of `A_(2)` is connected to a two litre flask containing two moles of `B_(2)`, how many moles of `AB` will be formed at `373 K`?

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The equilibrium constant for the reaction A_(2)(g) +B_(2) hArr 2AB(g) at 373 K is 50. If one litre flask containing one mole of A_(2) is connected to a two flask containing two moles of B_(2) , how many moles of AB will be formed at 373 K?

The K_(c) for A_(2(g))+B_(2(g))hArr2AB_((g)) at 100^(@)C is 50 . If one litre flasks containing one mole of A_(2) is connected with a two litre flask containing 2 "mole" of B_(2) , how many mole of AB will be formed at 100 ^(@)C ?

The K_(c) for A_(2(g))+B_(2(g))hArr2AB_((g)) at 100^(@)C is 50 . If one litre flasks containing one mole of A_(2) is connected with a two litre flask containing 2 "mole" of B_(2) , how many mole of AB will be formed at 100 ^(@)C ?

The equilibrium constant of the reaction A_(2)(g)+B_(2)(g) hArr 2AB(g) at 100^(@)C is 50 . If a 1L flask containing 1 mol of A_(2) is connected to a 2 L flask containing 2 mol of B_(2) , how many moles of AB will be formed at 373 K ?

The equilibrium constant of the reaction A_(2)(g)+B_(2)(g) hArr 2AB(g) at 100^(@)C is 50 . If a 1-L flask containing 1 mol of A_(2) is connected to a 2 L flask containing 2 mol of B_(2) , how many moles of AB will be formed at 373 K ?

The value of K_(c) for the reaction: A_(2)(g)+B_(2)(g) hArr 2AB(g) at 100^(@)C is 49 . If 1.0 L flask containing one mole of A_(2) is connected with a 2.0 L flask containing one mole of B_(2) , how many moles of AB will be formed at 100^(@)C ?