The geometry of ` [Ni(CN)_4]^(2-) `is

How will you account for the following : (i) [Fe(CN)_6]^(-) is weakly paramagnetic while [Ni(CN)_4]^(2+) diamagnetic. (ii) [Ni(CO)_4] possess tetrahedral geometry while [Ni(CN)_4]^(2-) is square planar.

The central metal ion in the complex makes available a number of empty orbitals for the formation of co-ordinate bonds with suitable ligands. The inner d-orbitals or outer d-orbitals are involved. The empty hybrid orbitals of metal ion overlap with the filled orbitals of ligand to from metal ligand co-ordinate bonds. For co-ordination number 6 octahedral geometry and sp^(3),d^(2)ord^(2)sp^(2) hybridisation involved and for cordiantion number 4 tetrahedral geometry, square planar geometry and sp^(3).dsp^(2) hybridisation involved. Geometry of [Ni(CN)_(4)]^(-2) ion is

The geometry of [NiCl_(4)]^(2-) and [Ni(PPh_(3))_(2)Cl_(2)] are :

The complex ion [Ni(CN)_4]^(2-) is :

The complex [NiCl_(4)]^(2-) has tetrahedral geometry while [Ni(CN)_(4)]^(2-) has square planar geometry. Explain.

Explain the geometry of [Ni (CO)_4] on basis of VBT.

The IUPAC name of [Ni(CN)_(4)]^(2-) is

The EAN of Ni in [Ni(CN)_(4)]^(2-) is

Statement-1 : [Ni(CO)_4] has square planar geometry while [Ni(CN)_4]^(4-) has tetrahedral geometry. Statement-2 : Geometry of above complexes depends upon the nature of ligands attached.