`P Q R` is a triangle in which `P Q=P R` and `S` is any point on the side `P Q` . Through `S ,` a line is drawn parallel to `Q R` and intersecting `P R` at `Tdot` Prove that `P S=P Tdot`

P Q R is a triangle is which P Q=P R\ a n d\ S is any point on the side P Q . Through S , a line is drawn parallel to Q R and intersecting P R\ at Tdot Prove that P S=P T

In P Q R , S is any point on the side Q R . Show that P Q+Q R+R P >2P S

P Q R S is a square. P R and S Q intersect at Odot State the measure of /_P O Qdot

P Q R S is a square. P R and S Q intersect at Odot State the measure of /_P O Qdot

In Figure, P Q R is a triangle and S is any point in its interior, show that SQ+SR < PQ+PR. Given : S is any point in the interior of P Q R To Prove : S Q+S R < P Q+P R Construction: Produce Q S to meet P R in T

In Figure, P Q R is a triangle and S is any point in its interior, show that S Q+S R

P Q R S is a square such that P R\ a n d\ S Q intersect at Odot State the measure of /_P O Q

P Q R S is a square such that P R\ a n d\ S Q intersect at Odot State the measure of /_P O Q

In Figure, /_P Q R=\ /_P R Q , then prove that /_P Q S=\ /_P R Tdot

In Fig 7.51, P R\ >\ P Q and PS bisects /_Q P R . Prove that /_P S R\ >/_P S Q .