The magneit moment of a transitio metal is ` sqrt(15)` B.M . Fin dout the mubner of unpaired electrons in it .

The magnetic moment of a transition metal ion is sqrt(15) B.M. Therefore the number of unpaired electrons present in it is

The magnetic moment of a transition metal ion is 3.87BM. The number of unpaired electrons present in it is

The magnetic moment of a transition metal ion is 3.87BM. The number of unpaired electrons present in it is

The magnetic moment of a transition metal ion is found to be 4.90 BM. The number of unpaired electrons present in the ion is

The magnetic moment of a transition metal ion is found to be 4.90 BM. The number of unpaired electrons present in the ion is

Presence of unpaired electrons makes a species paramagnetic. Each unpaired electron has a magnetic moment associated with its spin angular momentum and orbital angular momentum. For the compounds of the first series of transition metals, the contribution of the orbital angular momentum is effectively quenched and hence is considerably important. For these, the magnetic moment is determined by the number of unpaired electrons and is calculated by using the spin-only formula, i.e., mu = sqrt(n(n+2)) where n=number of unpaired electrons and mu =magnetic momentin (in Bohr magneton, B.M.). If n=1, then mu = 1.73 B.M . The magnetic moment of a transition metal ion is found to be 3.87 B.M. The number of unpaired electrons present in it is: