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The atomic number of cerium (Ce) is 58. ...

The atomic number of cerium (Ce) is 58. The correct electronic configuration of `Ce^(3+)` ion is

A

`[Xe]4f^(1)`

B

`[Kr]4f^(-1)`

C

`[Xe]4f^(-13)`

D

`[Kr]4d^(1)`

Text Solution

Verified by Experts

The correct Answer is:
A

For Z = 56, it will be `[Xe]6s^(2)`
In lanthanum (Z = 57), electrons should enter in 4f but to maintain stable xenon core it will go into 5d(difference is little in between 4f and 5d.)
But in cerium (Ce, Z = 58), electron enters into 4f.
`therefore" "Ce^(3+)=[Xe]4f^(1)`
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