The total mechanical energy of a harmonic oscillator of A =1 m and force constant ` 200 Nm^-1 is 150j`. Then

The total mechanical energy of a hamronic oscillator of amplitude 1m and force constant 200N//m is 150J . Then

Total mechanical energy of an oscillator is 160 J. Its force constant is 200 N/m and amplitude is 1m. Find its {:((1)" "KE_(max),(2)" "KE_(min)),((3)" "PE_(max),(4)" "PE_(min)):}

The total mechanical energy of a particle performing S.H.M. is 150 J with amplitude 1 m and force constant 200 N/m. Then minimum P.E. is,

The total mechanical energy of a particle performing S.H.M. is 150 J with amplitude 1 m and force constant 200 N/m . Then minimum P.E.

The total energy of a simple harmonic oscillation is proportional to

Calculate the maximum kinetic energy of a linear harmonic oscillator of force constant 12 xx 10^(5) N/m., amplitude 0.05 m.