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int(0)^(a){f(x)+f(-x)}dx-t...

int_(0)^(a){f(x)+f(-x)}dx-t

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int_(0)^(a)[f(x)+f(a-x)]dx=

Prove that int_(0)^(a)f(x)g(a-x)dx=int_(0)^(a)g(x)f(a-x)dx .

Prove that int_(0)^(2a)f(x)dx=int_(0)^(a)[f(a-x)+f(a+x)]dx

Prove that int_(0)^(2a)f(x)dx=int_(0)^(a)[f(a-x)+f(a+x)]dx

int_(0)^(a) (f(a+x) + f(a-x) ) dx =

Prove that: int_(-a)^(a) f(x) dx = {{:(2int_(0)^(a)f(x)dx, f(x) " is even "),(0, f(x) " is odd"):} and hence Evaluate int_(-t)^(t) sin^(5)(x)cos^(4)(x) dx

Let f(x) and g(x) be any two continuous function in the interval [0, b] and 'a' be any point between 0 and b. Which satisfy the following conditions : f(x)=f(a-x), g(x)+g(a-x)=3, f(a+b-x)=f(x) . Also int_(0)^(a)f(x)dx=int_(0)^(a)f(a-x)dx, int_(a)^(b)f(x)dx=int_(a)^(b)f(x)dx=int_(a)^(b)f(a+b-x)dx int_(0)^(a)f(x)dx=p" then " int_(0)^(a)f(x)g(x)dx is

Let f(x) be a continous function on R. If int_(0)^(1)[f(x)-f(2x)]dx=5 and int_(0)^(2)[f(x)-f(4x)]dx=10 then the value of int_(0)^(1)[f(x)-f(8x)]dx=

Prove that : int_(0)^(2a) f(x)dx=int_(0)^(a) f(x)dx+int_(0)^(a) f(x)dx+int_(0)^(a) f(2a-x)dx

prove that : int_(0)^(2a) f(x)dx = int_(0)^(a) f(x)dx + int_(0)^(a)f(2a-x)dx