The surface of a black body is at a temperature `727^(@)C` and its cross-section is `1 m^(2)`. Heat radiated from this surface in one minute in joules is (Stefan's constant = `5.7 xx 10^(-8) W//m^(2) // k^(4)`)

The surface of a black body is at a temperature 727^(@)C and its cross section is 1m^(2) Heat radiated from this surface in one minute in Joules is (Stefan's constant =5.7 xx 10^(-8) W//m^(2)//k^(4)) .

The surface of a black body is at a tempera ture 727^(@)C and its cross section is 1m^(2) Heat radi ated from this surface in one minute in Joules is (Stefan's constant =5.7 xx 10^(-8) W//m^(2)//k^(4)) .

A body at a temperature of 727^(@)C and having surface area 5 cm^(2) , radiations 300 J of energy each minute. The emissivity is(Given Boltzmann constant =5.67xx10^(-8) Wm^(-2)K^(-4)

A body at a temperature of 727^(@)C and having surface area 5 cm^(2) , radiations 300 J of energy each minute. The emissivity is(Given Boltzmann constant =5.67xx10^(-8) Wm^(-2)K^(-4)

What is the temperature at which a black body radiates heat at the rate of one kilowatt per unit area ? (Stefan 's constant sigma = 5.7 xx 10^(-8) S.Iunits)

Assuming a filament in a 100W light bulb acts like a perfect blackbody, what is the temperature of the hottest portion of the filament if it has a surface area of 6.3 xx 10^(-5) m^(2) ? The Stefan-Boltzmann constant is 5.67 xx 10^(-8) W //(m^(2).K^(2)) .

A body which has a surface area 5.00 cm^(2) and a temperature of 727^(@)C radiated 300 j of energy each minute. What is the emissivity of body? Steafan's constant =5.67xx10^(-8) Wm^(-2) K^(-4) .

Consider the sun to be a perfect sphere of radius 6.8 xx 10^(8)m . Calculate the energy radiated by sun in one minute. Surface temperature of the sun = 6200 K . Stefan's constant = 5.67 xx 10^(-8) J m^(-2) s^(-1) K^(-4) .

A hot body at 800^@C is radiating 500 J of energy per minute. Calculate the surface area of the body if emissivity is 0.23 and Stefan's constant is 5.67 xx 10^(-8) Wm^(-2) K^(.-4) .