सिध्द कीजिए कि : ` (sin^(2) A – sin^(2) B)/(sin A cos A – sin B cos B) = tan (A+ B)`

(sin ^(2) A - sin ^(2) B)/( sin A cos A - sin B cos B) is equal to

(sin A + sin B) / (cos A + cos B) = tan ((A + B) / (2))

(cos 2B - cos 2 A)/( sin 2 A + sin 2 B) = tan (A -B).

Prove that : (sin A - sin B)/ (cos A + cos B) + (cos A - cos B)/ (sin A + sin B) = 0

2sin^(2)B+4cos(A+B)sin A sin B+cos2(A+B)=

Prove that (sin A-sin B)/(cos A+ cos B) = "tan" (A-B)/2

If : A+B+C=pi, "then"" "sin ^(2) A +sin^(2)B - sin ^(2)C= A) 2 cos A * cos B * sin C B) 2 cos B * cos C * sin A C) 2 sin A * sin B * cos C D) 2 sin B * sin C * cos A

(sin (4A - 2B) + sin (4B - 2 A))/( cos (4 A - 2 B) + cos (4B - 2 A))= tan (A +B)

(sin(A+B)+cos A-sin(A-B))/(cos(A-B)+sin A-cos(A+B))=

Prove that (sin (4A - 2B) + sin (4B - 2A))/(cos (4A - 2B) + cos (4B - 2A)) = tan (A + B)