If the normal chord at `t` on `y^2= 4ax` subtends a right angle at vertex then `t^2=`

If a normal chord drawn at 't' on y^(2) = 4ax subtends a right angle at the focus then t^(2) =

The normal chord of the parabola y^(2)=4ax subtends a right angle at the vertex.Then the length of chord is

If a normal chord at a point on the parabola y^(2)=4ax subtends a right angle at the vertex, then t equals

If a normal chord at a point on the parabola y^(2)=4ax subtends a right angle at the vertex, then t equals

If normal chord a point 't' on the parabola y(2)=4ax subtends a right angle at vertex, then prove that t=+_sqrt(2)

A normal chord of the parabola y^2=4ax subtends a right angle at the vertex, find the slope of chord.

The normal chord of the parabola y^(2)=4ax subtends a right angle at the focus.Then the end point of the chord is