A straight line through the point A `(-2,-3)` cuts the line `x+3y=9` and `x+y+1=0` at B and C respectively. If AB.AC`=20` then equation of the possible line is

A straight line through the point A(-2, -3) cuts the line x+3y=9 and x+y+1=0 at B and C respectively. Find the equation of the line if AB.AC = 20 .

A straight line L passing through the point P(-2,-3) cuts the lines, x + 3y = 9 and x+y+1=0 at Q and R respectively. If (PQ) (PR) = 20 then the slope line L can be (A) 4 (B) 1 (C) 2 (D) 3

Two straight lines passing through the point A(3, 2) cut the line 2y=x+3 and x-axis perpendicularly at P and Q respectively. The equation of the line PQ is

A straight line through the point (2, 2) intersects the lines sqrt(3)x+y=0 and sqrt(3)x-y=0 at the points A and B. The equation of the line AB so that DeltaOAB is equilateral, is:

A straight line through the point (2, 2) intersects the lines sqrt3x + y = 0 and sqrt3 x-y=0 at the points A and B. The equation to the line AB so that the triangle OAB is equilateral is ,

A line through the point P(2,-3) meets the lines x-2y+7=0 and x+3y-3=0 at the points A and B respectively.If P divides AB externally in the ratio 3:2 then find the equation of the line AB.