The current in an `L-R` circuit builds upto `3//4th` of its steady state value in `4sec`. Then the time constant of this circuit is

The current in a LR circuit builds up to (3)/(4)th of its steady state value in 4s . The time constant of this circuit is

The current in a LR circuit builds up to 3/4 th of its steady state value in 4s. The time constant of this circuit is

The current in a LR circuit builds up to (3)/(40th of its steady state value ion 4s . The time constant. Of this circuit is

Current in an LR circuit attains one-fourth of its steady state value in 2 seconds. Calculate time constant for this circuit.

The current in an RL circuit builds up to one-third of its steady-state value in 5.00 s. Find the inductive time constant.

The time constant of L-R circuit is doubled if

In an LR-circuit the current attains one-third of its final steady value in 5s. What is the time-constant of the circuit ? (log_(2) = 0.405)