A particle is at x =+ 5 m at t =0,x =- 7 m at t = 6 s and x = + 2 at t = 10s. Find the average velocity of the particle during the intervals
(a)t=0 to t=6s
(b)t=6s to 6=10s
(c ) t=0 to t=10s .

Explanation

From the definition of average velocity
`x=(Deltax)/(Deltat)=(x_2-x_1)/(t_2-t_1)`
(a)The average velocity between the times t=0 to t= 6s
`x_1=+5m , t_1=0, x_2=-7` m `t_2`=6s
Hence `v_1=(x_2-x_1)/(t_2-t_1)=(-7-5)/(6-0)=-2 ms^(-1)`
(b)The average velocity between the times
`t_2`=6s to `t_3`=10 s is
`v_2=(x_3-x_2)/(t_3-t_2)=(2-(-7))/(10-6)=9/4=2.25ms^(-1)`
(c)The average velocity between times `t_1=0` to `t_3=10` s is
`v_3=(x_3-x_1)/(t_3-t_1)=(2-5)/(10-0)=-0.3 ms^(-1)`