A particle traversed half of the distance with a velocity of `V_0`. The remaining parts of the distance was covered with velocity `V_1` for half of the time and with `V_2` for other half of the time. Find the mean velocity of the particle averaged and the whole time of motion

Explanation

Average velocity for the second half distance = `(v_1 t/2 + v_2 t/2)/(t_2+t_2)=(v_1+v_2)/2`
Average velocity for the first half distance = `v_0` ( `because` it is constant)
Average velocity for total path
`=(2v_0(v_1+v_2)/2)/(v_0+(v_1+v_2)/2)=(2v_0(v_1+v_2))/(v_1+v_2+2v_0)`