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The displacement x of a particle at the ...

The displacement x of a particle at the instant when its velocity v is given by `v = sqrt(3x +16)`. Find its acceleration and initial velocity

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`v=sqrt(3x+16)` or `v^2`=3x+16
or `v^2-16=3x` Comparing with `v^2-u^2 =2as`
we get , u =4 units, 2a=3 or a=1.5 units .
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