A body starts from rest and moves with uniform acceleration of `5 ms^(-2)` for 8 seconds. From that time the acceleration ceases. Find the distance covered in 12s starting from rest.

Explanation

The velocity after 8 seconds v= 0 + 5 x 8 = 40 m/s
Distance covered in 8 seconds
`s_0=0+1/2xx5xx64`=160 m
After 8s the body moves with uniform velocity and distance covered in 4s with uniform velocity is
S=vt = 40 x 4 =160 m
The distance covered in 12 s = 160 +160 = 320 m.