A stone is allowed to fall from the top of a tower 300 m height and at the same time another stone is projected vertically up from the ground with a velocity `100 ms^(-1)` . Find when and where the two stones meet ?

Explanation

Suppose the two stones meet at a height x from ground after t seconds.
`x=100t-1/2 g t^2` …(1)
`300-x=0+1/2 g t^2`…(2)
Solve 1,2
t=3 sec, x=255.9 m