The ratio of the number of sp, `sp^(2)`, and `sp^(3)` orbitals in the compound is
`CH_(3)-CH=C=CH-C-=C-CH_(3)`

The ratio of the number of sp, sp2 and sp3 carbons in the compound given below is H_(2)C=C=CH-CH_3

The ratio of sp^(3),sp^(2) and sp carbons in the compound CH_(3)-CH=CH-C-=C-CH_(3) is

Give IUPAC names for the following compounds CH_(3)-CH=CH-CH=CH-C-=C-CH_(3)

What hybrid orbitals will form the following compound H_(3)C-CH=CH-CH_(2)-CH_(3)

Total number of sp^2 hybridised atoms present in the given compound is CH_2= CH- C= C - CN

Total number of sp hybridised atoms present in the given compound is CH_2= CH- C≡ C - CN

The hybrid orbitals involed in the formation of the C_(2) - C_(3) bond in the following compound, CH_(2)=CH-CH_(2)-CH_(2)-C-=CH are-

Total number of sp-hybridised C-atoms in the folowing Hydrocarbon will be :- H_(3)C-C-=C-CH=CH_(2)

Total number of sp-hybridised C-atoms in the folowing Hydrocarbon will be :- H_(3)C-C-=C-CH=CH_(2)