The volume of the gas mixture obtained by passing 400 mL `CO_(2)` over red hot coke was measured to be 600 mL. find the compo-sition of the gas mixture.

When CO_(2)(g) is passed over red hot coke it partially gets reduced to CO(g) . Upon passing 0.5 litre of CO_(2)(g) over red hot coke, the total volume of the gases increased to 700mL . The composition of the gaseous mixture at STP is :-

60 mL of a mixture of CO and H_(2) , mixed with 40 mL of O_(2) , are subjected to explosion in a eudiometer tube. On cooling the gas mixture after the end of the reaction, the volume is reduced to 30 mL. determine the compostion of the gas mixture initially taken. [All volumes are measured at the same temperature and pressure].

One litre of a mixture of CO and CO_2 is passed through red-hot charcoal. The volume now becomes 1.6 litre. Find the composition of the mixture by volume.

One litre of a mixture of CO and CO_2 is passed through red-hot charcoal. The volume now becomes 1.6 litre. Find the composition of the mixture by volume.

Which gas is obtained when CO_2 is passed over red hot coke ?

One litre of a mxiture of CO and CO_(2) is passed over red hot coke when the volume increased to 1.6 L under the same conditions of temperature and pressure . The volume of CO in the original mixture is

Under the same pressure and temperature, a mixture of 100 mL of water gas and 100 mL of O_(2) is subjected to explosion. Find the composition of the gas mixture formed by explosion under the same conditions of pressure and temperature.

When a mixture of air and steam is passed over red hot coke, the outgoing gas is:

When a mixture of air and steam is passed over red hot coke, the outgoing gas is:

A mixture of CO, CO_2 and He on passing over red hot coke shows 40 % increment in volume. What is the mole fraction of CO_2 in the given mixture ?