`(pi)/(4)+(2 pi)/(3)-(pi)/(6)`

(pi)/(4)+(pi)/(3)+(pi)/(6)

1+sinx + sin^2(x) + .... = 4+2sqrt3, 0ltxltpi, x!=pi, then x = 1) (pi)/(3), (pi)/(4) 2) (pi)/(4), (pi)/(6) 3) (2 pi)/(5), (pi)/(6) 4) (pi)/(3), (2 pi)/(3)

(pi)/(4)-(3 pi)/(4)-(pi)/(6)+(pi)/(4)=

If 4cos^(2)theta=3 then theta =---- 1) (pi)/(6),(5 pi)/(6) 2) (pi)/(4),(3 pi)/(4) 3) (pi)/(3),(2 pi)/(3) 4) +-(pi)/(2)

The angle between the lines whose direction cosines satisfy the equations l+m+n=0 and l^(2)=m^(2)+n^(2) is (1) (pi)/(3)(2)(pi)/(4)(3)(pi)/(6) (4) (pi)/(2)

The cotangent of the angles (pi)/(3),(pi)/(4),(pi)/(6) are in

The angle between the circles x^(2)+y^(2)-4x-6y-3=0 x^(2)+y^(2)+8x-4y+11=0 , 1.)(pi)/(2) 2.) (pi)/(4) 3.) (pi)/(6) 4.)(pi)/(6)

The solution set of the equation 4s int h eta cos theta-2cos theta-2sqrt(3)s int_(h eta)+sqrt(3)=0 in the interval (0,2 pi) is {(3 pi)/(4),(7 pi)/(4)} (b) {(pi)/(3),(5 pi)/(3)}{(3 pi)/(4),pi,(pi)/(3)(5 pi)/(3)}(d){(pi)/(6),(5 pi)/(6),(11 pi)/(6)}

The solution of 4sin^(2)x+tan^(2)x+csc^(2)x+cot^(2)x-6=0 is (n in Z)n pi+-(pi)/(4)(b)2n pi+-(pi)/(4)n pi+(pi)/(3)(d)n pi-(pi)/(6)

Prove that (i) " tan"^(2) .(pi)/(3) + 2cos^(2) .(pi)/(4)+ 3 sec^(2).(pi)/(6)+ 4 cos^(2).(pi)/(2)=8 (ii) " sin ".(pi)/(6) " cos 0 + sin ".(pi)/(4) " cos " .(pi)(4) + " sin " .(pi)/(3) "cos " .(pi)/(6) =(7)/(4) (iii) " 4sin " (pi)/(6) " sin"^(2) (pi)/(3) + 3 " cos " .(pi)/(3) " tan ".(pi)/(4) = " cosec"^(2).(pi)/(2)=4