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31(3+sqrt(3))(3-sqrt(3))" बराबर "...

31(3+sqrt(3))(3-sqrt(3))" बराबर "

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(3+sqrt3)(3-sqrt3)

(3 + sqrt3)(3 - sqrt3)

(3 + sqrt3)(3 - sqrt3)

(3 + sqrt3)(3 - sqrt3)

Simplify each of the following expressions: (i) (3+sqrt(3))(2+sqrt(2)) (ii) (3+sqrt(3))(3-sqrt(3)) (iii) (sqrt(5)-sqrt(2))(sqrt(5)+sqrt(2))

Which term of the GP sqrt(3), 1/sqrt(3), 1/(3sqrt(3)), 1/(9sqrt(3)) , ... Is 1/(729sqrt(3)) ?

3/(sqrt3 - sqrt3)

3/(sqrt3 - sqrt3)

The incenter of the triangle with vertices (1,sqrt(3)),(0,0), and (2,0) is (a) (1,(sqrt(3))/2) (b) (2/3,1/(sqrt(3))) (c) (2/3,(sqrt(3))/2) (d) (1,1/(sqrt(3)))

The incenter of the triangle with vertices (1,sqrt(3)),(0,0), and (2,0) is (a) (1,(sqrt(3))/2) (b) (2/3,1/(sqrt(3))) (c) (2/3,(sqrt(3))/2) (d) (1,1/(sqrt(3)))