An alternating emf given by `V = V_(0) sin omegat` has peak value 10 volt and freguency `50` Hz The instantaneous emf at .

The peak value of an alternating emf E given by E=(E_0) cos omega t is 10V and frequency is 50 Hz. At time t=(1//600)s the instantaneous value of emf is

The peak value of an alternating emf E given by E=(E_0) cos omega t is 10V and freqency is 50 Hz. At time t=(1//600)s the instantaneous value of emf is

An alternating e.m.f. is given by E=10 cos omega t . If the frequency is 50 Hz, then at time t=(1/600)s the instantaneous value of e.m.f. is

The peak value of an alternating emf E given by E = underset(o)(E) cos omega t is 10 V and frequency is 50 Hz . At time t = (1/600) s, the instantaneous value of emf is

An alternating e.m.f. given by e = 50 sin 314t is applied to a pure resistance of 100 ohm. Find:-peak value of e.m.f.

.The peak value of an alternating e.m.f. which is given by E=E_(0) coswt is 10 volts and its frequency is 50Hz .At time t=(1)/(600) s,the instantaneous e.m.f.is