The electric potential V is given as a function of distance x (metre) by `V = (6x^(2) + 10 x - 9)` volt. Find magnitude of electric field (in V/m) at x= 4.

The electric potential V is givne as a function of distance x (metre) by V = (5 x^(2) + 10x - 9) volt. Value of electric field at x = 1 is

The electric potential V is givne as a function of distance x (metre) by V = (5 x^(2) + 10x - 9) volt. Value of electric field at x = 1 is

The electric potential V is givne as a function of distance x (metre) by V = (5 x^(2) + 10x - 9) volt. Value of electric field at x = 1 is

The electric potential V as a function of distance x (meters) is given by V=(5x^(2)+10x-9) volt. The value of electric field at a point x=1m is

The electric potential V is a function of distance x in metre by V = ( 10x^2 - 5x + 3) volt. Value of electric field at x = 2 is,

The electric potential V as a function of distance x(in metre) is given by V= (2x^(2) + 5x-9)V The value of electic field at x=1m would be

The electric potential V at any point (x, y) in a plane is given by V=5x^(2)-4y^(2) volt. Find the magnitude of electric field intensity at the point (1m, 2m).

The figure gives the electric potential V as a function of distance through four regions , on x-axis. Which of the following is true for the magnitude of the electric field E in these regions?