In a chemical reaction, `Delta H = 150 kJ and Delta S = 100 JK^(-1)` at 300 K. Therefore, `Delta`G will be

In a chemical reaction DeltaH is 150 kJ and DeltaS is 100 J K^(-1) at 300 K then DeltaG is :-

In a chemical reaction triangleH =150kJ and triangleS = 100JK^-1 at 300K. The triangleG for the reaction is :

For a hypothetical reaction A(g) + 3B(g) to 2C(g). Delta H = -100 kJ and Delta S = -200 Jk^(-1) . Then the temperature at which the reaction will be in equilibrium is

For a hypothetical reaction A(g) + 3B(g) to 2C(g). Delta H = -100 kJ and Delta S = -200 Jk^(-1) . Then the temperature at which the reaction will be in equilibrium is

For a given reaction, Delta H = 35.5 kJ mol^(-1) and Delta S = 83.6 JK^(-1) mol(-1) . The reaction is spontaneous at : (Assume that Delta H and Delta S do not vary with temperature)