Home
Class 12
CHEMISTRY
Combustion of glucose takes place accord...

Combustion of glucose takes place according to the equation `C_(6)H_(12)O_(6)+6O_(2)` How much `rarr 6CO_(2)+6H_(2)O, DeltaH=-"72 kcal/mol"`.
energy will be released by the combustion of 1.6 g of glucose (Molecular mass of glucose = 180 g/mol)?

Promotional Banner

Similar Questions

Explore conceptually related problems

Combustion of glucose takes place according to the equation C_(6)H_(12)O_(6)+6O_(2) rarr 6CO_(2)+6H_(2)O, DeltaH=-"72 kcal/mol" . How much energy will be released by the combustion of 1.6 g of glucose (Molecular mass of glucose = 180 g/mol)?

Combustion fo glucose takes place according to the equation, C_(6)H_(12)O_(6)+6O_(2)rarr6CO_(2)+6H_(2)O,DeltaH=-72kcal How much energy will be required for the production of 1.6 g of glucose (Molecular mass of glucose=180g)

Find out the calorific value of Glucose C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O , Delta H=-2900 kJ/mole

Find out the calorific value of Glucose C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O , Delta H=-2900 kJ/mole

The equivalent weight of glucose in the reaction C_(6)H_(12)O_(6)+6O_(2)rarr 6CO_(2)+6H_(2)O is [M is molecular weight]