Home
Class 11
MATHS
If z is complex number, then the locus ...

If `z` is complex number, then the locus of `z` satisfying the condition `|2z-1|=|z-1|` is (a)perpendicular bisector of line segment joining 1/2 and 1 (b)circle (c)parabola (d)none of the above curves

Promotional Banner

Similar Questions

Explore conceptually related problems

Equation of perpendicular bisector of line joining z1and z2

The complex number z , which satisfies the condition |(1+z)/(1-z)|=1 lies on

If z_(1) and z_(2) are two complex numbers,then the equation of the perpendicular bisector ofthe segment joining z_(1) and z_(2) is

If a complex number z satisfies |z|^(2)+1=|z^(2)-1| , then the locus of z is

Show that the complex number z, satisfying the condition arg((z-1)/(z+1))=(pi)/(4) lie son a circle.

Show that the complex numbers z, satisfying the condition arg( frac{z-1}{z+1} ) = ( pi )/4 lies on a circle

The complex number z satisfying |z+bar(z)|+|z-bar(z)|=2 and |iz-1|+|z-1||=2 is/are

If z_1 and z_2 are two complex numbers, then the equation of the perpendicular bisector of the segment z_1 and z_2 is

The number of complex number Z satisfying the conditions |(Z)/(bar(z))+(bar(Z))/(Z)|=1,|Z|=1 and arg(z)=(0,2 pi) is

If z is a complex number satisfying the equation |z-(1+i)|^2=2 and omega=2/z , then the locus traced by 'omega' in the complex plane is