If C is centre of the ellipse `x^(2)/a^(2) + y^(2)/b^(2) = 1` and the normal at an end of a latusrectum cuts the major axis in G, then CG =

C is the centre of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2)) = 1 and L is an end of a latusrectum. If the normal at L meets the major axis at G then CG =

The tangent at point P on the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 cuts the minor axis in Q and PR is drawn perpendicular to the minor axis. If C is the centre of the ellipse, then CQ*CR =

The tangent at point P on the ellipse x^(2)/a^(2) + y^(2)/b^(2) = 1 cuts the minor axis in Q and PR is drawn perpendicular to the minor axis. If C is the centre of the ellipse, then CQ*CR =

C is the centre of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 and S is one of the foci. The ratio of C S to semi major axis is

C is the centre of the ellipse (x^(2))/(25)+(y^(2))/(16)=1 and S is one of the foci.The ratio of CS to semi major axis is

The maximum area of an isosceles triangle inscribed in the ellipse (x^2)/(a^2) + (y^2)/(b^2) = 1 with the vertex at one end of the major axis is

If for the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 , y-axis is the minor axis and the length of the latusrectum is one half of the length of its minor axis, then its eccentricity is