समीकरण `T=2pi sqrt(I/(mgl))` से आवर्तकाल मिलता है

Test if the following equations are dimensionally correct: (a) h=(2Scostheta)/(rhorg) (b). nu= sqrt(P/rho) , (c). V=(pi P r^4t)/(8etal), (d). v=(1)/(2pi) sqrt((mgl)/(I)) where h height, S= surface tension, rho = density, P= pressure, V=volume, eta = coefficient of viscosity, v= frequency and I = moment of inertia.

Test if the following equations are dimensionally correct: (a) h=(2Scostheta)/(rhorg) (b). nu= sqrt(P/rho) , (c). V=(pi P r^4t)/(8etal), (d). v=(1)/(2pi) sqrt((mgl)/(I)) where h height, S= surface tension, rho = density, P= pressure, V=volume, eta = coefficient of viscosity, v= frequency and I = moment of inertia.

Test if following equation is equation is dimensionally correct v=(1)/(2pi)sqrt((mgl)/(1)) where, v = frequency, I =moment of inertia, m= mass, l= lengh, g= acc. Due to gravity.

In triangle ABC , angle A = 90^@ , AD is the bisector of angle A meeting BC at D and DE bot AC at E. If AB =10cm and AC = 15 cm, then the length of DE, in cm is: triangle ABC में angle A=90^@ , AD, angle A का द्विभाजक है, जो BC से D पर मिलता है, और DE bot AC से E पर मिलता है। यदि AB = 10 cm और AC= 15 cm है, तो DE की लंबाई(cm) है,

Test if the following equations are dimensionally correct: a h=(2Scostheta)/(rhorg) b. nu= sqrt(P/rho), c. V=(pi P r^4t)/(8etal), d. v=(1)/(2pi) sqrt(mgl)/(I) where h height, S= surface tension, rho = density, P= pressure, V=volume, eta = coefficient of viscosity, v= frequency and I = moment of inertia.