If ` y=log (cosec x -cotx) ,then (dy)/(dx) `

Consider the following statements: 1. If y=ln(secx+tanx), then (dy)/(dx)=secx. 2. If y=ln("cosecx-cotx) , then (dy)/(dx)="cosec x". Which of the above is/are correct?

If y=log (log ( log x)) ,then (dy)/(dx)

Consider the following statements I. If y=ln(secx+tanx) . then (dy)/(dx)=secx II. If y=ln("cosec"x-cotx) . then (dy)/(dx)="cosec"x Which of the above statements is/are correct ?

If y= e^(cosec _x) ,then (dy)/(dx) =

If y= e^(log (log x )) ,then (dy)/(dx) =

If y= log tan x + log cotx , then (dy)/(dx) is

If log (x+y) =log (xy ) +a, then (dy)/(dx) =

y= 4 ^(log _ 2 cosec x)- 9 ^(log_3 cot x) ,then (dy)/(dx) =

If y=cot^(-1) ("cosec x"+cot x),"then " dy/dx=