The kinetic energy in J of 1 mole of `N_2` at `27^@ C` is
`(R= 8.314 mol^(-1) k^(-1))`

The kinetic energy of two moles of N_(2) at 27^(@) C is (R = 8.314 J K^(-1) mol^(-1))

The kinetic energy of two moles of N_(2) at 27^(@) C is (R = 8.314 J K^(-1) mol^(-1))

The kinetic enerrgy of 4 mole sof nitrogen gas at 127^(@)C is (R=2" cal "mol^(-1)K^(-1))

Kinetic energy in Kj of 280 g of N_(2) at 27^(@)C is approximately (R = 8. 314 J mol ^(-1) K ^(-1))

Find the kinetic energy of 8 g of oxygen at 27^@C (R = 8.3 J mol^(-1) K ^(-1) ).

Calculate the average kinetic energy of 8 g molecules of methane at 27^(@)C in joule. (R=8.314 JK^(-1) mol^(-1))

Calculate the average kinetic energy of oxygen molecule at 0^(@) C. (R=8.314 J mol^(-1) K^(-1),N_(A) = 6.02xx10^(23))