In the complex ion `[Cu(CN_(4))]^(3-)` the hybridization state, oxidation state and number of unpaired electrons of copper are respectively

[Cu(NH_(3))_(4)]^(2+) is a square planar complex.The number of unpaired electrons and hybrid state of copper are respectively

For the complex ion of [Co(NH_3)_6]^(3+) State the hybridization of the complex.

The hybrid state and oxidation state of S in SF_4 are respectively

The hybrid state and oxidation state of S in SF_4 are respectively

Calculate the coordination number of the metal ion , its oxidation state, number of electrons and number of unpaired electrons in d- orbitals respectively in complex [Co (H_(2) O)_(4) SO_(4)]Cl

Number of unpaired electrons in [Fe(CN)_6]^(4-) ion

For the complex ion [Fe(CN)_6]^(3-) state The geometry of the ion.