If `x= "Tanh"^(-1) y`, then `"log"_e ((1+y)/(1-y)) `=

If x = tan h^(-1)(y) then log_(e)((1+y)/(1-y))

If y^(x)= e^(y-x) , then prove that (dy)/(dx)= ((1+ log y)^(2))/(log y)

If x ^(y) = e ^( x -y) , then show that (dy)/(dx) = (log x )/( (1 + log x ) ^(2))

The solution of the differential equation, dy/dx=(x-y)^(2) , when y(1)=1, is (A) log_(e) abs((2-y)/(2-x))=2(y-1) (B) -log_(e)abs((1+x-y)/(1-x+y))=x+y-2 (C) log_(e) abs((2-x)/(2-y))=x-y (D) -log_(e) abs((1-x+y)/(1+x-y))=2(x-1)

If x,y,z are in G.P. (x,y,z gt 1) , then (1)/(2x+log_(e)x) , (1)/(4x+log_(e)y) , (1)/(6x+log_(ez)z) are in

If x,y,z are in G.P. (x,y,z gt 1) , then (1)/(2x+log_(e)x) , (1)/(4x+log_(e)y) , (1)/(6x+log_(ez)z) are in

If x,y,z are in G.P. (x,y,z gt 1) , then (1)/(2x+log_(e)x) , (1)/(4x+log_(e)y) , (1)/(6x+log_(ez)z) are in

If x,y,z are in G.P. (x,y,z gt 1) , then (1)/(2x+log_(e)x) , (1)/(4x+log_(e)y) , (1)/(6x+log_(ez)z) are in