`C("diamond")toC("Graphite")`, `DeltaH=-ve`. Then shows that

C(Diamond ) to C(Graphite), DeltaH =-ve, this indicates that _____

C ("diamond") rarr C ("graphite") , DeltaH = -ve , this indicates that

For the change, C_("diamond") to C_("graphite"), DeltaH = -1.89 kJ , if 6g of diamond and 6g of graphite are separately burnt to yield CO_2 , the heat liberated in first case is

For the transition C_("(diamond)") rarr C_("(graphite)"), DeltaH=-1.5 kJ . It follows that

For the transition C_("(diamond)") rarr C_("(graphite)"), DeltaH=-1.5 kJ . It follows that

Given that: i. C("graphite") +O_(2)(g) rarr CO_(2)(g), DeltaH =- 393.7 kJ ii. C("diamond") rarr C("graphite"), DeltaH =- 2.1 kJ a. Calculate DeltaH for buring of diamond of CO_(2) . b. Calculate the quantity of graphite that must be burnt to evolve 5000 kJ of heta.

Given that: i. C("graphite") +O_(2)(g) rarr CO_(2)(g), DeltaH =- 393.7 kJ ii. C("diamond") rarr C("graphite"), DeltaH =- 2.1 kJ a. Calculate DeltaH for buring of diamond of CO_(2) . b. Calculate the quantity of graphite that must be burnt to evolve 5000 kJ of heta.

Diamond And Graphite

Diamond And Graphite